Area and Perimeter of Basic Shapes
SAT area and perimeter questions like to combine shapes: a rectangle with a semicircle on one end, a ring between two circles, a square around a circle. Others ask what happens to the area when every side is scaled, or how to convert square feet to square yards.
Where I would start
Area is the space inside a shape, measured in square units. Perimeter is the distance around it, in plain units. For an unusual shape, split it into rectangles, triangles and pieces of circles, then add or subtract.
The reference sheet gives you the area of a circle, a rectangle and a triangle, and the circumference of a circle. It does not give the trapezoid, and it won't tell you which formula a question needs.
Formulas and question types
| Shape | Area | Perimeter |
|---|---|---|
| Rectangle | $A = \ell w$ | $P = 2\ell + 2w$ |
| Triangle | $A = \dfrac{1}{2}bh$ ($h$ is perpendicular to $b$) | Add the three sides |
| Circle | $A = \pi r^2$ | $C = 2\pi r = \pi d$ |
| Parallelogram | $A = bh$ | Add the four sides |
| Trapezoid | $A = \dfrac{1}{2}(b_1 + b_2)h$ | Add the four sides |
- Scaling: if every length is multiplied by $k$, the perimeter is multiplied by $k$ and the area by $k^2$.
- Square units: $1$ foot $= 12$ inches, so $1$ square foot $= 12^2 = 144$ square inches. $1$ yard $= 3$ feet, so $1$ square yard $= 9$ square feet.
Examples
The dashed line is inside the figure, so it is not part of the perimeter.
A rectangle with a semicircle
The figure shows a rectangle $20$ units long and $8$ units wide, with a semicircle on one short side. Find the area and the perimeter.
- The semicircle's diameter is the short side, $8$, so its radius is $4$.
- Area: rectangle $20 \cdot 8 = 160$, plus half a circle $\dfrac{1}{2}\pi(4)^2 = 8\pi$. Total $160 + 8\pi$.
- Perimeter: three sides of the rectangle, $20 + 8 + 20 = 48$, plus half the circumference, $\dfrac{1}{2} \cdot 2\pi(4) = 4\pi$. Total $48 + 4\pi$. The dashed side is not on the outside, so it is not counted.
The ring between two circles
Two circles share a center. The smaller has radius $7$ and the larger has radius $10$. What is the area of the region between them?
- Larger circle: $\pi(10)^2 = 100\pi$. Smaller circle: $\pi(7)^2 = 49\pi$.
- Subtract: $100\pi - 49\pi = 51\pi$.
- The answer is not $\pi(10 - 7)^2 = 9\pi$. You subtract the two areas, not the two radii.
Scaling a shape
A rectangle has an area of $30$ square units. Each side is tripled. What is the new area?
- Every length is multiplied by $3$, so the area is multiplied by $3^2 = 9$.
- $30 \cdot 9 = 270$ square units.
- Check with a $5$ by $6$ rectangle: the new one is $15$ by $18$, and $15 \cdot 18 = 270$.
Converting square units
A room is $12$ feet by $15$ feet. Carpet is sold by the square yard. How many square yards cover the floor?
- Area in square feet: $12 \cdot 15 = 180$.
- One square yard is $9$ square feet, so divide by $9$: $180 \div 9 = 20$ square yards.
- Or convert first: the room is $4$ yards by $5$ yards, which is $20$ square yards.
Where students lose points
- Using a slanted side as the height. The height of a triangle or parallelogram must be perpendicular to the base.
- Counting an inside edge in the perimeter. When shapes are joined, the shared side is no longer on the outside.
- Mixing up radius and diameter. If a semicircle sits on a side of length $8$, its radius is $4$.
- Scaling area by $k$ instead of $k^2$. Doubling every side makes the area four times as large.
- Converting square units with the linear factor. Square feet to square inches uses $144$, not $12$.
Practice
Draw each figure and label it before you start. Then open the solution to compare.
- A$14$
- B$28$
- C$48$
- D$56$
Show solution
- A$10\pi$
- B$20\pi$
- C$100\pi$
- D$25\pi$
Show solution
Show solution
- A$3\pi$
- B$9\pi$
- C$51\pi$
- D$149\pi$
Show solution
- A$160 + 4\pi$
- B$160 + 16\pi$
- C$160 + 64\pi$
- D$160 + 8\pi$
Show solution
Show solution
- A$v + v\sqrt{2}$
- B$2v + v\sqrt{2}$
- C$3v$
- D$\dfrac{v + v\sqrt{2}}{2}$
Show solution
- A\$500
- B\$1,500
- C\$4,500
- D\$166.67
Show solution
Show solution
- A$100 - 100\pi$
- B$100 - 25\pi$
- C$100 - 10\pi$
- D$75\pi$
Show solution
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