Ratios and Proportions on the SAT
Most ratio questions are not hard, and that is exactly why points get lost here. Students rush, use the wrong total, put the units in different places on each side of a proportion, or forget that areas and volumes do not scale the way lengths do.
Start here
A ratio of $3 : 5$ means $3$ parts of one thing for every $5$ parts of the other. To turn it into real amounts, call one part $k$. The amounts are $3k$ and $5k$, and the total is $8k$.
For rates and recipes, set up a proportion with the same units in the same places on both sides, then cross-multiply. For unit conversions, multiply by fractions equal to $1$ until the units you don't want cancel.
Worked examples
A ratio and a total
The ratio of boys to girls in a class is $3 : 5$. There are $40$ students. How many are girls?
- Boys $= 3k$, girls $= 5k$, total $= 8k$.
- $8k = 40$, so $k = 5$.
- Girls $= 5k = 25$. Using $\dfrac{5}{3}$ of something, or dividing $40$ by $5$, are the usual slips.
Combining two ratios
$a : b = 2 : 3$ and $b : c = 4 : 5$. What is $a : c$?
- The shared term $b$ is $3$ in one ratio and $4$ in the other. Make both $12$.
- $a : b = 8 : 12$ and $b : c = 12 : 15$.
- So $a : c = 8 : 15$.
A ratio that changes
A bag has red and blue marbles in the ratio $4 : 7$. After $6$ red marbles are added, the ratio is $2 : 3$. How many blue marbles are there?
- Before: red $= 4k$, blue $= 7k$. After: red $= 4k + 6$, blue still $7k$.
- $\dfrac{4k + 6}{7k} = \dfrac{2}{3}$. Cross-multiply: $12k + 18 = 14k$, so $k = 9$.
- Blue $= 7k = 63$. Check: red becomes $42$, and $42 : 63 = 2 : 3$.
Converting units
Convert $72$ kilometers per hour to meters per second.
- $72 \dfrac{\text{km}}{\text{h}} \cdot \dfrac{1{,}000 \text{ m}}{1 \text{ km}} \cdot \dfrac{1 \text{ h}}{3{,}600 \text{ s}}$.
- The kilometers and hours cancel, leaving $\dfrac{72{,}000}{3{,}600} = 20$ meters per second.
What the questions look like
- A ratio and a total. Write the parts as $3k$ and $5k$, add them, set equal to the total, solve for $k$.
- A rate, find a new amount. Proportion: $\dfrac{12 \text{ gal}}{315 \text{ mi}} = \dfrac{20 \text{ gal}}{x \text{ mi}}$. Same units across from each other.
- A scale on a map or drawing. Multiply the drawing length by the scale factor.
- Two ratios sharing a term ($a:b$ and $b:c$). Rescale both so the shared term is the same number, then read $a : c$.
- A ratio that changes after adding some. Write the before amounts as $4k$ and $7k$, add to one, set the new ratio equal, and solve.
- Similar figures. Lengths scale by $k$, areas by $k^2$, volumes by $k^3$.
Watch out for these
- Using the wrong total. In a $3 : 5$ ratio, the whole is $8$ parts. Girls are $\dfrac{5}{8}$ of the class, not $\dfrac{5}{3}$.
- Mismatched proportions. If gallons are on top on the left, gallons go on top on the right.
- Combining ratios without matching the shared term. From $2 : 3$ and $4 : 5$ you cannot just read $2 : 5$.
- Scaling area like length. If lengths are $2.5$ times bigger, the area is $2.5^2 = 6.25$ times bigger.
- Flipping a conversion factor. Check that the unit you want to get rid of appears once on top and once on the bottom.
Practice
Write the ratio as amounts with $k$ before you calculate anything.
- A$15$
- B$24$
- C$25$
- D$8$
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- A$2 : 5$
- B$10 : 12$
- C$8 : 15$
- D$15 : 8$
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- A$525$
- B$500$
- C$540$
- D$323$
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- A$\dfrac{3}{7}$
- B$\dfrac{4}{7}$
- C$\dfrac{7}{3}$
- D$\dfrac{7}{4}$
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- A$2$
- B$9$
- C$15$
- D$6$
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- A$30$
- B$75$
- C$60$
- D$187.5$
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