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Applying Exponent Rules

SAT Math · Advanced Math · Updated June 2026

A handful of exponent rules cover most of what the SAT asks — the errors come from mixing up when to add and when to multiply.

Reading the concept isn't enough. The score comes from practicing the real Bluebook-style format and finding the exact mistakes you keep making.

What the SAT tests here

Same base, multiplying: add exponents. Same base, dividing: subtract. Power of a power: multiply. These only apply when the bases match.

How to solve one, step by step

Example: simplify $\frac{x^5 \cdot x^2}{x^3}$.

  1. Multiply on top (add exponents): $x^{5+2} = x^7$.
  2. Divide (subtract): $x^{7-3} = x^4$.

The mistakes that cost points

Practice questions

Try these the way you would on test day, then open the solution to check your method.

Easy
Which of the following is equivalent to $\frac{(a^3)^4}{a^5}$?
  • A$a^{60}$
  • B$a^2$
  • C$a^7$
  • D$a^{17}$
Show solution
Answer: C, $a^7$. First apply the power rule to the numerator: $(a^3)^4 = a^{3 \cdot 4} = a^{12}$. Then apply the quotient rule: $\frac{a^{12}}{a^5} = a^{12-5} = a^7$.
Medium
Simplify $\dfrac{12(m^{6})^{3}}{3m}$
  • A$4m^{8}$
  • B$9m^{17}$
  • C$4m^{18}$
  • D$4m^{17}$
Show solution
Answer: D, $4m^{17}$. Apply the power rule: $(m^{6})^{3} = m^{18}$. The expression becomes $\dfrac{12m^{18}}{3m}$. Divide the coefficients: $\dfrac{12}{3} = 4$. Apply the quotient rule: $\dfrac{m^{18}}{m} = m^{18-1} = m^{17}$. The simplified expression is $4m^{17}$.
Hard
Simplify $\dfrac{30(-x^{5})^{3}}{6x}$
  • A$-24x^{14}$
  • B$-5x^{14}$
  • C$-5x^{15}$
  • D$5x^{14}$
Show solution
Answer: B, $-5x^{14}$. Apply the power rule, tracking the sign carefully. $(-x^{5})^{3} = (-1)^{3} \cdot x^{15}$. Since the exponent 3 is odd, $(-x^{5})^{3} = -x^{15}$. The expression becomes $\dfrac{-30x^{15}}{6x}$. Divide the coefficients: $\dfrac{30}{6} = 5$. Apply the quotient rule: $\dfrac{x^{15}}{x} = x^{15-1} = x^{14}$. The simplified expression is $-5x^{14}$.

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