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Solving Linear Equations on the SAT

SAT Math · Algebra · Updated October 2026

Where I would start

Undo what was done to $x$, in reverse order, and do the same thing to both sides every time. Clear parentheses and fractions first, gather the $x$ terms on one side, and then divide.

The SAT adds two twists. Sometimes there is a constant like $k$, which you find by putting the given solution into the equation. And sometimes you are asked whether an equation has one solution, no solution or infinitely many.

Linear equations are the most common question type in SAT Math. Most of them are quick, so when students lose points here it is usually a small slip: a sign dropped while distributing, a fraction that was not cleared from every term, or an answer for $x$ when the question asked for something else.

The question types

You seeDo this
ParenthesesDistribute first, including any minus sign: $-2(x - 4) = -2x + 8$.
FractionsMultiply every term on both sides by the least common denominator.
$x$ on both sidesMove all $x$ terms to one side and all numbers to the other.
A constant $k$ and a given solutionSubstitute the solution for $x$, then solve for $k$.
"How many solutions?"Simplify to $ax + b = cx + d$. If $a \neq c$: one solution. If $a = c$ and $b \neq d$: no solution. If $a = c$ and $b = d$: infinitely many.
"What is the value of $2x - 3$?"Look for that expression inside the equation before solving for $x$. It is often a single step away.

How I work through them

Example 1: finding a constant

The equation $5(x + k) - 5 = 20$ has the solution $x = 3$. What is $k$?

  1. Substitute $x = 3$: $5(3 + k) - 5 = 20$.
  2. Add $5$: $5(3 + k) = 25$. Divide by $5$: $3 + k = 5$.
  3. $k = 2$.

Example 2: clearing fractions

Solve $\dfrac{x}{3} + \dfrac{x}{4} = 7$.

  1. The least common denominator is $12$. Multiply every term by $12$: $4x + 3x = 84$.
  2. $7x = 84$, so $x = 12$.
  3. Check: $\dfrac{12}{3} + \dfrac{12}{4} = 4 + 3 = 7$.

Example 3: no solution or infinitely many

For what value of $k$ does $3(2x - 1) = 6x + k$ have infinitely many solutions?

  1. Distribute: $6x - 3 = 6x + k$.
  2. The $x$ terms already match on both sides. If the constants match too, every $x$ works.
  3. So $k = -3$. Any other value of $k$ gives no solution at all.

Example 4: solving for an expression

If $4x - 6 = 10$, what is the value of $2x - 3$?

  1. Notice that $4x - 6$ is exactly $2(2x - 3)$.
  2. So $2(2x - 3) = 10$, and $2x - 3 = 5$.
  3. Solving for $x$ first ($x = 4$) also works, but it takes longer and gives you one more chance to slip.

Small slips that cost points

Practice questions

Do these the way you would on test day, then open each solution to check your method, not only your answer.

Easy
What value of $x$ satisfies $3x + 7 = 22$?
  • A$3$
  • B$5$
  • C$\dfrac{29}{3}$
  • D$15$
Show solution
Answer: B. Subtract $7$: $3x = 15$. Divide by $3$: $x = 5$. Choice C adds $7$ instead of subtracting it.
EasyStudent-produced response
The equation $2(3x + k) = 22$ has the solution $x = 2$, where $k$ is a constant. What is the value of $k$?
Enter your answer.
Show solution
Answer: $5$. Substitute $x = 2$: $2(6 + k) = 22$. Divide by $2$: $6 + k = 11$, so $k = 5$.
Medium
The equation $5(x + k) - 5 = 20$ has the solution $x = 3$, where $k$ is a constant. What is the value of $k$?
  • A$1$
  • B$5$
  • C$3$
  • D$2$
Show solution
Answer: D. Substitute $x = 3$: $5(3 + k) - 5 = 20$, so $5(3 + k) = 25$, $3 + k = 5$, and $k = 2$. Choice B is the value of $3 + k$, not $k$.
MediumStudent-produced response
What is the solution to $\dfrac{x}{3} + \dfrac{x}{4} = 7$?
Enter your answer.
Show solution
Answer: $12$. Multiply every term by $12$: $4x + 3x = 84$, so $7x = 84$ and $x = 12$.
Medium
If $4x - 6 = 10$, what is the value of $2x - 3$?
  • A$4$
  • B$8$
  • C$5$
  • D$13$
Show solution
Answer: C. $4x - 6 = 2(2x - 3)$, so $2(2x - 3) = 10$ and $2x - 3 = 5$. Choice A is the value of $x$.
Medium
In the equation $3x + 22 = kx + 4$, $k$ is a constant and $k \neq 3$. Which expression gives $x$ in terms of $k$?
  • A$\dfrac{18}{3 - k}$
  • B$\dfrac{26}{k - 3}$
  • C$-\dfrac{18}{k + 3}$
  • D$\dfrac{18}{k - 3}$
Show solution
Answer: D. Move the $x$ terms to one side: $3x - kx = 4 - 22$, so $x(3 - k) = -18$. Then $x = \dfrac{-18}{3 - k}$. Multiplying the top and bottom by $-1$ gives $\dfrac{18}{k - 3}$. Choice A drops the minus sign.
Hard
How many solutions does the equation $4(x - 2) + 3 = 2(2x - 1) - 3$ have?
  • AExactly one
  • BInfinitely many
  • CZero
  • DExactly two
Show solution
Answer: B. Simplify each side. Left: $4x - 8 + 3 = 4x - 5$. Right: $4x - 2 - 3 = 4x - 5$. The two sides are identical, so every value of $x$ works.
HardStudent-produced response
In the equation $3(2x - 1) = 6x + k$, $k$ is a constant. If the equation has infinitely many solutions, what is the value of $k$?
Enter your answer.
Show solution
Answer: $-3$. Distribute: $6x - 3 = 6x + k$. The $x$ terms match, so the equation is true for every $x$ only when the constants match too: $k = -3$.
Hard
In the equation $ax + 5 = 3x - 2$, $a$ is a constant. For what value of $a$ does the equation have no solution?
  • A$-3$
  • B$0$
  • C$3$
  • D$5$
Show solution
Answer: C. With $a = 3$, the equation becomes $3x + 5 = 3x - 2$, which simplifies to $5 = -2$. That is never true, so there is no solution. Any other value of $a$ gives exactly one solution.
HardStudent-produced response
A plumber charges a \$60 visit fee plus \$45 for each hour of work. A customer's bill was \$217.50. How many hours did the plumber work?
Enter your answer.
Show solution
Answer: $3.5$ (or $\dfrac{7}{2}$). Let $h$ be the number of hours: $60 + 45h = 217.5$. Subtract $60$: $45h = 157.5$. Divide by $45$: $h = 3.5$.

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